| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
If c = 4 and x = -3, what is the value of 6c(c - x)?
| -70 | |
| 108 | |
| 168 | |
| -50 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
6c(c - x)
6(4)(4 + 3)
6(4)(7)
(24)(7)
168
Solve for y:
-9y - 1 = 3 - 5y
| 2\(\frac{1}{3}\) | |
| -\(\frac{7}{9}\) | |
| -\(\frac{2}{7}\) | |
| -1 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-9y - 1 = 3 - 5y
-9y = 3 - 5y + 1
-9y + 5y = 3 + 1
-4y = 4
y = \( \frac{4}{-4} \)
y = -1
Solve 8c - 9c = 3c + y + 2 for c in terms of y.
| \(\frac{5}{12}\)y - \(\frac{1}{3}\) | |
| -3y - 9 | |
| 2y + \(\frac{2}{5}\) | |
| \(\frac{1}{3}\)y - \(\frac{5}{6}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
8c - 9y = 3c + y + 2
8c = 3c + y + 2 + 9y
8c - 3c = y + 2 + 9y
5c = 10y + 2
c = \( \frac{10y + 2}{5} \)
c = \( \frac{10y}{5} \) + \( \frac{2}{5} \)
c = 2y + \(\frac{2}{5}\)
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
|
deconstructing |
|
normalizing |
|
factoring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
What is 3a7 + 7a7?
| -4 | |
| 10a7 | |
| 21a14 | |
| a714 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
3a7 + 7a7 = 10a7