ASVAB Math Knowledge Practice Test 923467 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

Solve for c:
8c - 2 = \( \frac{c}{9} \)

46% Answer Correctly
\(\frac{16}{35}\)
\(\frac{18}{71}\)
9\(\frac{3}{5}\)
\(\frac{4}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

8c - 2 = \( \frac{c}{9} \)
9 x (8c - 2) = c
(9 x 8c) + (9 x -2) = c
72c - 18 = c
72c - 18 - c = 0
72c - c = 18
71c = 18
c = \( \frac{18}{71} \)
c = \(\frac{18}{71}\)


2

Which of the following statements about math operations is incorrect?

70% Answer Correctly

you can multiply monomials that have different variables and different exponents

all of these statements are correct

you can add monomials that have the same variable and the same exponent

you can subtract monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


3

The dimensions of this cylinder are height (h) = 1 and radius (r) = 2. What is the volume?

62% Answer Correctly
36π
162π
128π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(22 x 1)
v = 4π


4

The dimensions of this cylinder are height (h) = 8 and radius (r) = 9. What is the surface area?

48% Answer Correctly
64π
306π
224π
144π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 8)
sa = 2π(81) + 2π(72)
sa = (2 x 81)π + (2 x 72)π
sa = 162π + 144π
sa = 306π


5

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
\( \sqrt{2} \)
8\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)