| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
The dimensions of this trapezoid are a = 5, b = 4, c = 6, d = 3, and h = 3. What is the area?
| 35 | |
| 10\(\frac{1}{2}\) | |
| 10 | |
| 16\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(4 + 3)(3)
a = ½(7)(3)
a = ½(21) = \( \frac{21}{2} \)
a = 10\(\frac{1}{2}\)
The endpoints of this line segment are at (-2, 7) and (2, -5). What is the slope of this line?
| -\(\frac{1}{2}\) | |
| -2\(\frac{1}{2}\) | |
| -1 | |
| -3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, -5) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-5.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)Solve for c:
c2 + 9c - 10 = 4c + 4
| 8 or -6 | |
| 8 or -7 | |
| 2 or -7 | |
| -3 or -8 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 + 9c - 10 = 4c + 4
c2 + 9c - 10 - 4 = 4c
c2 + 9c - 4c - 14 = 0
c2 + 5c - 14 = 0
Next, factor the quadratic equation:
c2 + 5c - 14 = 0
(c - 2)(c + 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 2) or (c + 7) must equal zero:
If (c - 2) = 0, c must equal 2
If (c + 7) = 0, c must equal -7
So the solution is that c = 2 or -7
If the base of this triangle is 9 and the height is 1, what is the area?
| 45 | |
| 4\(\frac{1}{2}\) | |
| 82\(\frac{1}{2}\) | |
| 49 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 1 = \( \frac{9}{2} \) = 4\(\frac{1}{2}\)
A coordinate grid is composed of which of the following?
y-axis |
|
origin |
|
all of these |
|
x-axis |
The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.