When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 5c = 4c + x + 2 for c in terms of x.
| -1\(\frac{2}{3}\)x - \(\frac{1}{3}\) | |
| -x + \(\frac{9}{10}\) | |
| -2x + 1 | |
| 3x + 1\(\frac{1}{4}\) |