| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.63 |
| Score | 0% | 53% |
The dimensions of this trapezoid are a = 5, b = 7, c = 8, d = 9, and h = 4. What is the area?
| 32 | |
| 24 | |
| 30 | |
| 22\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(7 + 9)(4)
a = ½(16)(4)
a = ½(64) = \( \frac{64}{2} \)
a = 32
Find the value of c:
4c + x = 8
-2c + x = 5
| \(\frac{1}{2}\) | |
| -1\(\frac{5}{41}\) | |
| 1\(\frac{9}{17}\) | |
| \(\frac{1}{3}\) |
You need to find the value of c so solve the first equation in terms of x:
4c + x = 8
x = 8 - 4c
then substitute the result (8 - 4c) into the second equation:
-2c + 1(8 - 4c) = 5
-2c + (1 x 8) + (1 x -4c) = 5
-2c + 8 - 4c = 5
-2c - 4c = 5 - 8
-6c = -3
c = \( \frac{-3}{-6} \)
c = \(\frac{1}{2}\)
The endpoints of this line segment are at (-2, -4) and (2, 6). What is the slope of this line?
| 2\(\frac{1}{2}\) | |
| -2 | |
| 1\(\frac{1}{2}\) | |
| 2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -4) and (2, 6) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(6.0) - (-4.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
|
bisects |
|
midpoints |
|
trisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.
If a = c = 4, b = d = 8, what is the area of this rectangle?
| 35 | |
| 32 | |
| 81 | |
| 48 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 4 x 8
a = 32