ASVAB Math Knowledge Practice Test 927694 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

Solve -3b + 9b = 3b - 5z + 7 for b in terms of z.

34% Answer Correctly
\(\frac{1}{18}\)z + \(\frac{2}{9}\)
-\(\frac{2}{7}\)z + \(\frac{5}{7}\)
-4z + 1\(\frac{2}{3}\)
2\(\frac{1}{3}\)z - 1\(\frac{1}{6}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-3b + 9z = 3b - 5z + 7
-3b = 3b - 5z + 7 - 9z
-3b - 3b = -5z + 7 - 9z
-6b = -14z + 7
b = \( \frac{-14z + 7}{-6} \)
b = \( \frac{-14z}{-6} \) + \( \frac{7}{-6} \)
b = 2\(\frac{1}{3}\)z - 1\(\frac{1}{6}\)


2

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
5\( \sqrt{2} \)
6\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


3

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

84% Answer Correctly

Inside

Last

First

Odd


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


4

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

intersects

trisects

midpoints

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


5

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

deconstructing

normalizing

factoring

squaring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.