When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 2c = 6c + 5z - 8 for c in terms of z.
| \(\frac{1}{2}\)z - \(\frac{3}{4}\) | |
| -\(\frac{7}{10}\)z + \(\frac{4}{5}\) | |
| \(\frac{2}{11}\)z + \(\frac{4}{11}\) | |
| \(\frac{5}{8}\)z + \(\frac{3}{4}\) |