When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 3c = -4c + 9x + 5 for c in terms of x.
| 1\(\frac{1}{5}\)x + \(\frac{1}{2}\) | |
| -2x - 3 | |
| -1\(\frac{1}{6}\)x + 1\(\frac{1}{6}\) | |
| 2x + 4 |