| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
The dimensions of this cylinder are height (h) = 3 and radius (r) = 3. What is the surface area?
| 140π | |
| 160π | |
| 306π | |
| 36π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 3)
sa = 2π(9) + 2π(9)
sa = (2 x 9)π + (2 x 9)π
sa = 18π + 18π
sa = 36π
If side a = 4, side b = 4, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{32} \) | |
| \( \sqrt{13} \) | |
| \( \sqrt{145} \) | |
| \( \sqrt{90} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 42 + 42
c2 = 16 + 16
c2 = 32
c = \( \sqrt{32} \)
The formula for the area of a circle is which of the following?
a = π r |
|
a = π d2 |
|
a = π r2 |
|
a = π d |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Solve for y:
-3y - 8 < -7 + 3y
| y < -\(\frac{1}{6}\) | |
| y < -\(\frac{1}{2}\) | |
| y < -1\(\frac{1}{2}\) | |
| y < -\(\frac{2}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-3y - 8 < -7 + 3y
-3y < -7 + 3y + 8
-3y - 3y < -7 + 8
-6y < 1
y < \( \frac{1}{-6} \)
y < -\(\frac{1}{6}\)
A quadrilateral is a shape with __________ sides.
3 |
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2 |
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4 |
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5 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.