| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
Solve 3a + 8a = -4a + 8y - 1 for a in terms of y.
| y - \(\frac{1}{7}\) | |
| \(\frac{1}{6}\)y + \(\frac{1}{12}\) | |
| -\(\frac{2}{3}\)y - 1\(\frac{2}{3}\) | |
| \(\frac{1}{6}\)y + \(\frac{2}{9}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
3a + 8y = -4a + 8y - 1
3a = -4a + 8y - 1 - 8y
3a + 4a = 8y - 1 - 8y
7a = - 1
a = \( \frac{ - 1}{7} \)
a = \( \frac{}{7} \) + \( \frac{-1}{7} \)
a = y - \(\frac{1}{7}\)
Simplify (2a)(4ab) - (2a2)(2b).
| 24ab2 | |
| 12a2b | |
| 24a2b | |
| 4a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(4ab) - (2a2)(2b)
(2 x 4)(a x a x b) - (2 x 2)(a2 x b)
(8)(a1+1 x b) - (4)(a2b)
8a2b - 4a2b
4a2b
If side x = 13cm, side y = 9cm, and side z = 8cm what is the perimeter of this triangle?
| 23cm | |
| 32cm | |
| 30cm | |
| 28cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 13cm + 9cm + 8cm = 30cm
On this circle, line segment CD is the:
circumference |
|
chord |
|
diameter |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If BD = 6 and AD = 13, AB = ?
| 7 | |
| 14 | |
| 4 | |
| 12 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD