When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 8c = -c + 6z + 2 for c in terms of z.
| 3\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| -\(\frac{1}{4}\)z + 1 | |
| 2z + \(\frac{4}{7}\) | |
| 1\(\frac{3}{5}\)z + \(\frac{4}{5}\) |