When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 8c = -3c + 6z + 2 for c in terms of z.
| -\(\frac{1}{3}\)z - \(\frac{2}{3}\) | |
| \(\frac{2}{5}\)z - \(\frac{2}{5}\) | |
| -2z + \(\frac{4}{5}\) | |
| 5z + 6 |