| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.87 |
| Score | 0% | 57% |
Solve for a:
-5a + 7 < \( \frac{a}{-8} \)
| a < \(\frac{7}{64}\) | |
| a < 1\(\frac{17}{39}\) | |
| a < 1 | |
| a < \(\frac{4}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-5a + 7 < \( \frac{a}{-8} \)
-8 x (-5a + 7) < a
(-8 x -5a) + (-8 x 7) < a
40a - 56 < a
40a - 56 - a < 0
40a - a < 56
39a < 56
a < \( \frac{56}{39} \)
a < 1\(\frac{17}{39}\)
The endpoints of this line segment are at (-2, 7) and (2, -5). What is the slope of this line?
| \(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) | |
| -3 | |
| -\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 7) and (2, -5) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-5.0) - (7.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)Simplify (y + 3)(y - 8)
| y2 - 5y - 24 | |
| y2 + 11y + 24 | |
| y2 - 11y + 24 | |
| y2 + 5y - 24 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 3)(y - 8)
(y x y) + (y x -8) + (3 x y) + (3 x -8)
y2 - 8y + 3y - 24
y2 - 5y - 24
If a = 5, b = 5, c = 3, and d = 2, what is the perimeter of this quadrilateral?
| 25 | |
| 15 | |
| 23 | |
| 32 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 5 + 5 + 3 + 2
p = 15
Solve for b:
2b - 5 = \( \frac{b}{-9} \)
| -\(\frac{35}{43}\) | |
| 2\(\frac{7}{19}\) | |
| \(\frac{7}{36}\) | |
| \(\frac{63}{64}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
2b - 5 = \( \frac{b}{-9} \)
-9 x (2b - 5) = b
(-9 x 2b) + (-9 x -5) = b
-18b + 45 = b
-18b + 45 - b = 0
-18b - b = -45
-19b = -45
b = \( \frac{-45}{-19} \)
b = 2\(\frac{7}{19}\)