The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b² + 8b - 11 = 2b - 4
b² + 8b - 11 + 4 = 2b
b² + 8b - 2b - 7 = 0
b² + 6b - 7 = 0

Next, factor the quadratic equation:

b² + 6b - 7 = 0
(b - 1)(b + 7) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 1) or (b + 7) must equal zero:

If (b - 1) = 0, b must equal 1
If (b + 7) = 0, b must equal -7

So the solution is that b = 1 or -7

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

b + 6z = 3b - 8z + 1
b = 3b - 8z + 1 - 6z
b - 3b = -8z + 1 - 6z
-2b = -14z + 1
b = \( \frac{-14z + 1}{-2} \)
b = \( \frac{-14z}{-2} \) + \( \frac{1}{-2} \)
b = 7z - \(\frac{1}{2}\)

You need to find the value of b so solve the first equation in terms of x:

3b + x = -4
x = -4 - 3b

then substitute the result (-4 - 3b) into the second equation:

5b - 8(-4 - 3b) = -2
5b + (-8 x -4) + (-8 x -3b) = -2
5b + 32 + 24b = -2
5b + 24b = -2 - 32
29b = -34
b = \( \frac{-34}{29} \)
b = -1\(\frac{5}{29}\)

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s²).

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.