When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c + 6c = 7c + 2z + 3 for c in terms of z.
| \(\frac{3}{4}\)z - \(\frac{3}{4}\) | |
| -\(\frac{1}{7}\)z - 1\(\frac{2}{7}\) | |
| -\(\frac{1}{7}\)z + \(\frac{3}{14}\) | |
| \(\frac{4}{9}\)z - \(\frac{1}{3}\) |