ASVAB Math Knowledge Practice Test 938759 Results

Your Results Global Average
Questions 5 5
Correct 0 2.76
Score 0% 55%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

2(π r2) + 2π rh

4π r2

π r2h

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

Solve 2c + c = c + 5y - 6 for c in terms of y.

34% Answer Correctly
\(\frac{3}{7}\)y - \(\frac{4}{7}\)
4y - 6
4y + 4
-6y - 4

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

2c + y = c + 5y - 6
2c = c + 5y - 6 - y
2c - c = 5y - 6 - y
c = 4y - 6


3

If side x = 14cm, side y = 7cm, and side z = 12cm what is the perimeter of this triangle?

84% Answer Correctly
33cm
45cm
21cm
42cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 14cm + 7cm + 12cm = 33cm


4

Which of the following statements about a triangle is not true?

57% Answer Correctly

exterior angle = sum of two adjacent interior angles

perimeter = sum of side lengths

area = ½bh

sum of interior angles = 180°


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


5

Solve for y:
y2 - 17 = 2y - 2

48% Answer Correctly
8 or -3
5 or -5
-3 or 5
1 or -4

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 - 17 = 2y - 2
y2 - 17 + 2 = 2y
y2 - 2y - 15 = 0
y2 - 2y - 15 = 0

Next, factor the quadratic equation:

y2 - 2y - 15 = 0
(y + 3)(y - 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 3) or (y - 5) must equal zero:

If (y + 3) = 0, y must equal -3
If (y - 5) = 0, y must equal 5

So the solution is that y = -3 or 5