ASVAB Math Knowledge Practice Test 939202

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 6a = 6a + 3x + 5 for a in terms of x.

-\(\frac{10}{11}\)x + \(\frac{7}{11}\)
-2\(\frac{1}{3}\)x + \(\frac{2}{3}\)
-4\(\frac{1}{2}\)x - 2\(\frac{1}{2}\)
2\(\frac{1}{2}\)x - 1\(\frac{1}{2}\)