ASVAB Math Knowledge Practice Test 939492 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

On this circle, line segment AB is the:

70% Answer Correctly

radius

chord

circumference

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

Find the value of c:
-2c + y = -2
c + 7y = -5

42% Answer Correctly
2\(\frac{3}{17}\)
-\(\frac{30}{49}\)
\(\frac{3}{5}\)
3

Solution

You need to find the value of c so solve the first equation in terms of y:

-2c + y = -2
y = -2 + 2c

then substitute the result (-2 - -2c) into the second equation:

c + 7(-2 + 2c) = -5
c + (7 x -2) + (7 x 2c) = -5
c - 14 + 14c = -5
c + 14c = -5 + 14
15c = 9
c = \( \frac{9}{15} \)
c = \(\frac{3}{5}\)


3

The dimensions of this cylinder are height (h) = 6 and radius (r) = 5. What is the volume?

62% Answer Correctly
288π
128π
150π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(52 x 6)
v = 150π


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

addition

exponents

pairs

division


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

Simplify (6a)(2ab) + (5a2)(3b).

65% Answer Correctly
27a2b
27ab2
64ab2
64a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(2ab) + (5a2)(3b)
(6 x 2)(a x a x b) + (5 x 3)(a2 x b)
(12)(a1+1 x b) + (15)(a2b)
12a2b + 15a2b
27a2b