To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

5y - 5 = \( \frac{y}{-8} \)
-8 x (5y - 5) = y
(-8 x 5y) + (-8 x -5) = y
-40y + 40 = y
-40y + 40 - y = 0
-40y - y = -40
-41y = -40
y = \( \frac{-40}{-41} \)
y = \(\frac{40}{41}\)

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c² + 15c + 82 = -3c + 1
c² + 15c + 82 - 1 = -3c
c² + 15c + 3c + 81 = 0
c² + 18c + 81 = 0

Next, factor the quadratic equation:

c² + 18c + 81 = 0
(c + 9)(c + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (c + 9) must equal zero:

If (c + 9) = 0, c must equal -9

So the solution is that c = -9

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.