| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.50 |
| Score | 0% | 50% |
Solve for x:
-6x - 7 = -8 + 3x
| \(\frac{1}{9}\) | |
| -1\(\frac{1}{7}\) | |
| -2 | |
| -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-6x - 7 = -8 + 3x
-6x = -8 + 3x + 7
-6x - 3x = -8 + 7
-9x = -1
x = \( \frac{-1}{-9} \)
x = \(\frac{1}{9}\)
Which of the following is not required to define the slope-intercept equation for a line?
y-intercept |
|
\({\Delta y \over \Delta x}\) |
|
slope |
|
x-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
Solve for z:
z2 - 9z + 18 = 0
| -7 or -7 | |
| 9 or 3 | |
| 2 or -1 | |
| 3 or 6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 - 9z + 18 = 0
(z - 3)(z - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 3) or (z - 6) must equal zero:
If (z - 3) = 0, z must equal 3
If (z - 6) = 0, z must equal 6
So the solution is that z = 3 or 6
On this circle, a line segment connecting point A to point D is called:
radius |
|
chord |
|
circumference |
|
diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The endpoints of this line segment are at (-2, 3) and (2, 1). What is the slope of this line?
| 2 | |
| -2 | |
| -3 | |
| -\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (3.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)