| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
Order the following types of angle from least number of degrees to most number of degrees.
acute, right, obtuse |
|
right, obtuse, acute |
|
right, acute, obtuse |
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acute, obtuse, right |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If side x = 13cm, side y = 15cm, and side z = 5cm what is the perimeter of this triangle?
| 33cm | |
| 25cm | |
| 32cm | |
| 35cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 13cm + 15cm + 5cm = 33cm
On this circle, line segment AB is the:
circumference |
|
chord |
|
diameter |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve for x:
x2 - x - 30 = 0
| -5 or 6 | |
| 3 or -5 | |
| 6 or -2 | |
| 1 or -6 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
x2 - x - 30 = 0
(x + 5)(x - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 5) or (x - 6) must equal zero:
If (x + 5) = 0, x must equal -5
If (x - 6) = 0, x must equal 6
So the solution is that x = -5 or 6
On this circle, line segment CD is the:
diameter |
|
chord |
|
radius |
|
circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).