ASVAB Math Knowledge Practice Test 944328

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2c + 3c = 2c + 5y - 1 for c in terms of y.

-12y + 3
4y - 2
-1\(\frac{1}{4}\)y + \(\frac{1}{4}\)
-\(\frac{1}{2}\)y + \(\frac{1}{4}\)