ASVAB Math Knowledge Practice Test 944933

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + 5a = 4a - 4z - 7 for a in terms of z.

\(\frac{2}{3}\)z - 2\(\frac{1}{3}\)
-4\(\frac{1}{2}\)z - 3\(\frac{1}{2}\)
\(\frac{2}{13}\)z + \(\frac{2}{13}\)
\(\frac{1}{8}\)z - \(\frac{1}{2}\)