When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c + 5c = 2c + z - 5 for c in terms of z.
| z - 4 | |
| \(\frac{1}{2}\)z + \(\frac{5}{8}\) | |
| -\(\frac{10}{13}\)z - \(\frac{7}{13}\) | |
| -1\(\frac{3}{14}\)z + \(\frac{3}{14}\) |