When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve b + 4b = -2b + 9z + 1 for b in terms of z.
| z + 2\(\frac{2}{3}\) | |
| -3\(\frac{2}{3}\)z - 2\(\frac{1}{3}\) | |
| 1\(\frac{1}{3}\)z - 2 | |
| 1\(\frac{2}{3}\)z + \(\frac{1}{3}\) |