When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 5c = 5c - 4z + 6 for c in terms of z.
| -\(\frac{1}{2}\)z - 3 | |
| \(\frac{2}{3}\)z + 1\(\frac{2}{3}\) | |
| 4z + 2 | |
| -1\(\frac{3}{8}\)z + \(\frac{3}{8}\) |