ASVAB Math Knowledge Practice Test 947683 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

Solve for z:
z2 - 6z - 27 = 0

57% Answer Correctly
7 or 6
9 or -4
9 or -1
-3 or 9
Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

z2 - 6z - 27 = 0
(z + 3)(z - 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 3) or (z - 9) must equal zero:

If (z + 3) = 0, z must equal -3
If (z - 9) = 0, z must equal 9

So the solution is that z = -3 or 9

2

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

normalizing

squaring

deconstructing

factoring
Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.

3

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c - a

c2 - a2

a2 - c2

c2 + a2

Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)

4

If AD = 21 and BD = 16, AB = ?

75% Answer Correctly
5
16
17
19
Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 21 - 16
AB = 5

5

Find the value of c:
3c + y = 2
-4c + 8y = 5

42% Answer Correctly
\(\frac{11}{26}\)
1\(\frac{7}{16}\)
\(\frac{11}{28}\)
-1\(\frac{14}{23}\)
Solution

You need to find the value of c so solve the first equation in terms of y:

3c + y = 2
y = 2 - 3c

then substitute the result (2 - 3c) into the second equation:

-4c + 8(2 - 3c) = 5
-4c + (8 x 2) + (8 x -3c) = 5
-4c + 16 - 24c = 5
-4c - 24c = 5 - 16
-28c = -11
c = \( \frac{-11}{-28} \)
c = \(\frac{11}{28}\)