ASVAB Math Knowledge Practice Test 947741

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7c + 5c = c + 3x - 2 for c in terms of x.

x + 2
-\(\frac{1}{3}\)x - \(\frac{1}{3}\)
2\(\frac{3}{5}\)x + 1\(\frac{3}{5}\)
-\(\frac{3}{5}\)x - \(\frac{4}{5}\)