When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7c - 8c = c - 3z - 1 for c in terms of z.
| \(\frac{5}{6}\)z - \(\frac{1}{6}\) | |
| -1\(\frac{2}{5}\)z + \(\frac{1}{5}\) | |
| \(\frac{5}{12}\)z - \(\frac{1}{2}\) | |
| -2\(\frac{4}{5}\)z - 1\(\frac{1}{5}\) |