ASVAB Math Knowledge Practice Test 949610

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8a + 2a = 3a - y - 6 for a in terms of y.

-\(\frac{4}{5}\)y + \(\frac{1}{15}\)
\(\frac{1}{2}\)y - \(\frac{2}{3}\)
-\(\frac{1}{7}\)y - 1
-\(\frac{3}{5}\)y - 1\(\frac{1}{5}\)