ASVAB Math Knowledge Practice Test 949661 Results

	Your Results	Global Average
Questions	5	5
Correct	0	2.91
Score	0%	58%

Review

The endpoints of this line segment are at (-2, -2) and (2, -4). What is the slope of this line?

46% Answer Correctly

	2
	-\(\frac{1}{2}\)
	1\(\frac{1}{2}\)
	-1\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, -4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)
m = -\(\frac{1}{2}\)

What is the area of a circle with a radius of 2?

69% Answer Correctly

	49π
	4π
	2π
	7π

Solution

The formula for area is πr²:

a = πr²
a = π(2²)
a = 4π

Factor y² - 7y + 12

53% Answer Correctly

	(y + 4)(y + 3)
	(y + 4)(y - 3)
	(y - 4)(y + 3)
	(y - 4)(y - 3)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 12 as well and sum (Inside, Outside) to equal -7. For this problem, those two numbers are -4 and -3. Then, plug these into a set of binomials using the square root of the First variable (y²):

y² - 7y + 12
y² + (-4 - 3)y + (-4 x -3)
(y - 4)(y - 3)

Which of the following statements about math operations is incorrect?

70% Answer Correctly

	you can subtract monomials that have the same variable and the same exponent
	you can add monomials that have the same variable and the same exponent
	you can multiply monomials that have different variables and different exponents
	all of these statements are correct

Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a² - a² = 3a² but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

	2(π r²) + 2π rh
	π r²h²
	π r²h
	4π r²

Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r²h and the surface area is 2(π r²) + 2π rh.