When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6a + 6a = -6a - 5z + 4 for a in terms of z.
| \(\frac{1}{3}\)z - \(\frac{5}{12}\) | |
| -\(\frac{5}{9}\)z - \(\frac{1}{9}\) | |
| -\(\frac{11}{12}\)z + \(\frac{1}{3}\) | |
| \(\frac{1}{6}\)z - \(\frac{1}{6}\) |