ASVAB Math Knowledge Practice Test 954963 Results

Your Results Global Average
Questions 5 5
Correct 0 2.84
Score 0% 57%

Review

1

Solve for b:
8b + 5 = \( \frac{b}{-7} \)

46% Answer Correctly
-\(\frac{35}{57}\)
\(\frac{1}{6}\)
-\(\frac{2}{5}\)
1\(\frac{4}{23}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

8b + 5 = \( \frac{b}{-7} \)
-7 x (8b + 5) = b
(-7 x 8b) + (-7 x 5) = b
-56b - 35 = b
-56b - 35 - b = 0
-56b - b = 35
-57b = 35
b = \( \frac{35}{-57} \)
b = -\(\frac{35}{57}\)


2

What is 5a6 + 6a6?

75% Answer Correctly
11a6
a612
30a12
11a12

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a6 + 6a6 = 11a6


3

Factor y2 - y - 6

54% Answer Correctly
(y - 3)(y - 2)
(y + 3)(y + 2)
(y + 3)(y - 2)
(y - 3)(y + 2)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -6 as well and sum (Inside, Outside) to equal -1. For this problem, those two numbers are -3 and 2. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - y - 6
y2 + (-3 + 2)y + (-3 x 2)
(y - 3)(y + 2)


4

Solve for c:
2c + 6 = 8 + 5c

59% Answer Correctly
\(\frac{2}{3}\)
-\(\frac{5}{8}\)
-\(\frac{2}{3}\)
-7

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

2c + 6 = 8 + 5c
2c = 8 + 5c - 6
2c - 5c = 8 - 6
-3c = 2
c = \( \frac{2}{-3} \)
c = -\(\frac{2}{3}\)


5

The dimensions of this cylinder are height (h) = 3 and radius (r) = 3. What is the surface area?

48% Answer Correctly
168π
16π
12π
36π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 3)
sa = 2π(9) + 2π(9)
sa = (2 x 9)π + (2 x 9)π
sa = 18π + 18π
sa = 36π