ASVAB Math Knowledge Practice Test 955795 Results

Your Results Global Average
Questions 5 5
Correct 0 3.55
Score 0% 71%

Review

1

If AD = 18 and BD = 12, AB = ?

76% Answer Correctly
6
14
8
10

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 18 - 12
AB = 6


2

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

the area of a parallelogram is base x height

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

If a = 7 and x = 5, what is the value of 8a(a - x)?

69% Answer Correctly
160
-27
112
-12

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

8a(a - x)
8(7)(7 - 5)
8(7)(2)
(56)(2)
112


4

A coordinate grid is composed of which of the following?

91% Answer Correctly

y-axis

x-axis

all of these

origin


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
2\( \sqrt{2} \)
7\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)