When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - 4c = -c + 5x - 1 for c in terms of x.
| -4\(\frac{1}{2}\)x + \(\frac{1}{2}\) | |
| -\(\frac{1}{2}\)x + 4 | |
| -4x - 5 | |
| 3\(\frac{1}{3}\)x - 2\(\frac{2}{3}\) |