ASVAB Math Knowledge Practice Test 95699 Results

Your Results Global Average
Questions 5 5
Correct 0 3.09
Score 0% 62%

Review

1

Simplify (y - 9)(y - 6)

64% Answer Correctly
y2 - 15y + 54
y2 - 3y - 54
y2 + 15y + 54
y2 + 3y - 54

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y - 9)(y - 6)
(y x y) + (y x -6) + (-9 x y) + (-9 x -6)
y2 - 6y - 9y + 54
y2 - 15y + 54


2

Simplify (8a)(2ab) - (2a2)(3b).

63% Answer Correctly
10a2b
22ab2
50a2b
50ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(2ab) - (2a2)(3b)
(8 x 2)(a x a x b) - (2 x 3)(a2 x b)
(16)(a1+1 x b) - (6)(a2b)
16a2b - 6a2b
10a2b


3

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

84% Answer Correctly

First

Last

Inside

Odd


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


4

Solve for b:
-2b - 8 > \( \frac{b}{2} \)

45% Answer Correctly
b > -\(\frac{42}{55}\)
b > \(\frac{35}{48}\)
b > -3\(\frac{1}{5}\)
b > -\(\frac{5}{8}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-2b - 8 > \( \frac{b}{2} \)
2 x (-2b - 8) > b
(2 x -2b) + (2 x -8) > b
-4b - 16 > b
-4b - 16 - b > 0
-4b - b > 16
-5b > 16
b > \( \frac{16}{-5} \)
b > -3\(\frac{1}{5}\)


5

The dimensions of this trapezoid are a = 5, b = 6, c = 6, d = 5, and h = 3. What is the area?

51% Answer Correctly
16\(\frac{1}{2}\)
28
24
18

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 5)(3)
a = ½(11)(3)
a = ½(33) = \( \frac{33}{2} \)
a = 16\(\frac{1}{2}\)