ASVAB Math Knowledge Practice Test 957881 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and right

equilateral, isosceles and right

isosceles and right

equilateral and isosceles


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


2

Which of the following statements about math operations is incorrect?

71% Answer Correctly

you can subtract monomials that have the same variable and the same exponent

all of these statements are correct

you can add monomials that have the same variable and the same exponent

you can multiply monomials that have different variables and different exponents


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


3

Solve for x:
7x - 5 = \( \frac{x}{2} \)

46% Answer Correctly
-\(\frac{4}{29}\)
-3\(\frac{3}{23}\)
\(\frac{7}{16}\)
\(\frac{10}{13}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

7x - 5 = \( \frac{x}{2} \)
2 x (7x - 5) = x
(2 x 7x) + (2 x -5) = x
14x - 10 = x
14x - 10 - x = 0
14x - x = 10
13x = 10
x = \( \frac{10}{13} \)
x = \(\frac{10}{13}\)


4

A right angle measures:

91% Answer Correctly

180°

360°

45°

90°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


5

Simplify (5a)(8ab) - (6a2)(4b).

62% Answer Correctly
130a2b
130ab2
64ab2
16a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(8ab) - (6a2)(4b)
(5 x 8)(a x a x b) - (6 x 4)(a2 x b)
(40)(a1+1 x b) - (24)(a2b)
40a2b - 24a2b
16a2b