When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b - 4b = 3b - 2z - 3 for b in terms of z.
| \(\frac{2}{3}\)z - 1 | |
| \(\frac{1}{2}\)z + 4 | |
| -2\(\frac{1}{3}\)z + 2 | |
| -1\(\frac{1}{10}\)z + \(\frac{7}{10}\) |