| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.49 |
| Score | 0% | 50% |
The endpoints of this line segment are at (-2, -2) and (2, 10). What is the slope of this line?
| \(\frac{1}{2}\) | |
| 1\(\frac{1}{2}\) | |
| -1\(\frac{1}{2}\) | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, 10) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(10.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{12}{4} \)A cylinder with a radius (r) and a height (h) has a surface area of:
4π r2 |
|
2(π r2) + 2π rh |
|
π r2h |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
The dimensions of this trapezoid are a = 5, b = 8, c = 8, d = 8, and h = 3. What is the area?
| 12 | |
| 25\(\frac{1}{2}\) | |
| 24 | |
| 18 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(8 + 8)(3)
a = ½(16)(3)
a = ½(48) = \( \frac{48}{2} \)
a = 24
Solve for y:
y - 1 < \( \frac{y}{5} \)
| y < 1\(\frac{1}{4}\) | |
| y < \(\frac{10}{23}\) | |
| y < -\(\frac{9}{82}\) | |
| y < 1\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
y - 1 < \( \frac{y}{5} \)
5 x (y - 1) < y
(5 x y) + (5 x -1) < y
5y - 5 < y
5y - 5 - y < 0
5y - y < 5
4y < 5
y < \( \frac{5}{4} \)
y < 1\(\frac{1}{4}\)
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
|
equilateral, isosceles and right |
|
equilateral and right |
|
equilateral and isosceles |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.