ASVAB Math Knowledge Practice Test 961979

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c + c = -c + y + 3 for c in terms of y.

\(\frac{3}{4}\)y + \(\frac{1}{4}\)
-2\(\frac{5}{6}\)y - 1\(\frac{1}{3}\)
y + 1\(\frac{1}{2}\)
2y - 2