When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 5c = -9c - 6z + 6 for c in terms of z.
| -2z + 1\(\frac{2}{5}\) | |
| -\(\frac{1}{5}\)z + 1\(\frac{1}{5}\) | |
| -\(\frac{1}{2}\)z - 1\(\frac{3}{4}\) | |
| -\(\frac{1}{3}\)z - \(\frac{1}{3}\) |