When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 9c = 8c + 4x + 2 for c in terms of x.
| -2\(\frac{1}{3}\)x + \(\frac{1}{3}\) | |
| -5x + 2 | |
| -1\(\frac{3}{5}\)x - \(\frac{4}{5}\) | |
| 3\(\frac{1}{4}\)x + 2 |