When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6a + 8a = 3a + z - 8 for a in terms of z.
| 16z + 5 | |
| -\(\frac{5}{12}\)z - \(\frac{1}{6}\) | |
| 7z - 2 | |
| -2\(\frac{1}{3}\)z - 2\(\frac{2}{3}\) |