| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.72 |
| Score | 0% | 54% |
The dimensions of this cube are height (h) = 4, length (l) = 6, and width (w) = 7. What is the surface area?
| 54 | |
| 120 | |
| 288 | |
| 188 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 6 x 7) + (2 x 7 x 4) + (2 x 6 x 4)
sa = (84) + (56) + (48)
sa = 188
If BD = 10 and AD = 17, AB = ?
| 7 | |
| 2 | |
| 14 | |
| 15 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDWhich of the following is not true about both rectangles and squares?
the perimeter is the sum of the lengths of all four sides |
|
all interior angles are right angles |
|
the area is length x width |
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the lengths of all sides are equal |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
Solve -7b - 3b = -5b - 2z + 8 for b in terms of z.
| 1\(\frac{3}{7}\)z - \(\frac{1}{7}\) | |
| -\(\frac{1}{2}\)z - 4 | |
| 5\(\frac{1}{3}\)z - \(\frac{1}{3}\) | |
| \(\frac{1}{3}\)z + \(\frac{1}{6}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-7b - 3z = -5b - 2z + 8
-7b = -5b - 2z + 8 + 3z
-7b + 5b = -2z + 8 + 3z
-2b = z + 8
b = \( \frac{z + 8}{-2} \)
b = \( \frac{z}{-2} \) + \( \frac{8}{-2} \)
b = -\(\frac{1}{2}\)z - 4
The endpoints of this line segment are at (-2, 1) and (2, -9). What is the slope of this line?
| -2\(\frac{1}{2}\) | |
| -3 | |
| -\(\frac{1}{2}\) | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -9) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-9.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-10}{4} \)