| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.72 |
| Score | 0% | 54% |
Which types of triangles will always have at least two sides of equal length?
equilateral, isosceles and right |
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equilateral and isosceles |
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isosceles and right |
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equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
Solve for x:
x2 + 8x - 43 = 5x - 3
| 5 or -5 | |
| 2 or -8 | |
| 5 or -8 | |
| 8 or -1 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
x2 + 8x - 43 = 5x - 3
x2 + 8x - 43 + 3 = 5x
x2 + 8x - 5x - 40 = 0
x2 + 3x - 40 = 0
Next, factor the quadratic equation:
x2 + 3x - 40 = 0
(x - 5)(x + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (x - 5) or (x + 8) must equal zero:
If (x - 5) = 0, x must equal 5
If (x + 8) = 0, x must equal -8
So the solution is that x = 5 or -8
On this circle, line segment CD is the:
diameter |
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radius |
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chord |
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circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
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c - a |
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c2 - a2 |
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c2 + a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
If AD = 13 and BD = 11, AB = ?
| 4 | |
| 14 | |
| 6 | |
| 2 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD