When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c - 3c = -7c - 3x + 9 for c in terms of x.
| 2\(\frac{2}{3}\)x + \(\frac{2}{3}\) | |
| x + \(\frac{9}{16}\) | |
| 1\(\frac{3}{8}\)x + \(\frac{1}{8}\) | |
| \(\frac{1}{3}\)x + \(\frac{1}{4}\) |