When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + c = 8c + 6z - 9 for c in terms of z.
| -2\(\frac{1}{2}\)z + 4\(\frac{1}{2}\) | |
| 1\(\frac{2}{13}\)z - \(\frac{9}{13}\) | |
| -\(\frac{1}{4}\)z - 1 | |
| -\(\frac{5}{13}\)z - \(\frac{3}{13}\) |