ASVAB Math Knowledge Practice Test 969028

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -a - 2a = 3a - 4z - 6 for a in terms of z.

\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)
-\(\frac{8}{11}\)z - \(\frac{8}{11}\)
\(\frac{1}{5}\)z + \(\frac{3}{5}\)
-\(\frac{11}{16}\)z + \(\frac{7}{16}\)