| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.75 |
| Score | 0% | 55% |
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
2(π r2) + 2π rh |
|
4π r2 |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
The endpoints of this line segment are at (-2, -7) and (2, 1). What is the slope of this line?
| 1 | |
| 2 | |
| 2\(\frac{1}{2}\) | |
| -1 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -7) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-7.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)Simplify (9a)(6ab) - (9a2)(8b).
| 255ab2 | |
| 255a2b | |
| 126ab2 | |
| -18a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(9a)(6ab) - (9a2)(8b)
(9 x 6)(a x a x b) - (9 x 8)(a2 x b)
(54)(a1+1 x b) - (72)(a2b)
54a2b - 72a2b
-18a2b
What is the area of a circle with a radius of 3?
| 4π | |
| 3π | |
| 9π | |
| 64π |
The formula for area is πr2:
a = πr2
a = π(32)
a = 9π
Solve for z:
-6z - 1 = \( \frac{z}{-5} \)
| -1\(\frac{4}{5}\) | |
| -\(\frac{5}{29}\) | |
| -\(\frac{9}{13}\) | |
| -2\(\frac{13}{16}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-6z - 1 = \( \frac{z}{-5} \)
-5 x (-6z - 1) = z
(-5 x -6z) + (-5 x -1) = z
30z + 5 = z
30z + 5 - z = 0
30z - z = -5
29z = -5
z = \( \frac{-5}{29} \)
z = -\(\frac{5}{29}\)