ASVAB Math Knowledge Practice Test 97534

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c + 4c = 3c - 5x - 5 for c in terms of x.

\(\frac{2}{5}\)x + \(\frac{1}{5}\)
x - \(\frac{2}{9}\)
4\(\frac{1}{2}\)x + 2\(\frac{1}{2}\)
5\(\frac{1}{2}\)x + 4\(\frac{1}{2}\)